Here’s the solution to the 12 Balls puzzle that I mentioned a few days (gosh…a few weeks now) ago . To state it again:
You have 12 identical-looking balls. One of these balls has a different weight from all the others. You also have a two-pan balance for comparing weights. Using the balance in the smallest number of times possible, determine which ball has the unique weight, and also determine whether it is heavier or lighter than the others.
The third branch following the 1st decision is left blank because it is very similar to the 1st one. The larger image file is available here.
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